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Logic AND Gate Tutorial

Logic AND Gate Tutorial

The Logic AND Gate is a type of digital logic circuit whose output goes HIGH to a logic level 1 only when all of its inputs are HIGH

The output state of a digital logic AND gate only returns “LOW” again when ANY of its inputs are at a logic level “0”. In other words for a logic AND gate, any LOW input will give a LOW output.

The logic or Boolean expression given for a digital AND gate is that for Logical Multiplication which is denoted by a single dot or full stop symbol, ( . ) giving us the Boolean expression of:  A.B = Q.

Then we can define the operation of a digital 2-input AND gate as being:

 

“If both A and B are true, then Q is true”

2-input Transistor AND Gate

A simple 2-input AND gate can be constructed using RTL Resistor-transistor switches connected together as shown below with the inputs connected directly to the transistor bases. Both transistors must be saturated “ON” for an output at Q.

2-input transistor circuit

 

Logic AND Gates are available using digital circuits to produce the desired logical function and is given a symbol whose shape represents the logical operation of the AND gate.

Digital AND Gate Types

The 2-input Logic AND Gate

Symbol Truth Table
2-input function

 

2-input AND Gate
B A Q
0 0 0
0 1 0
1 0 0
1 1 1
Boolean Expression Q = A.B Read as A AND B gives Q

The 3-input Logic AND Gate

Symbol Truth Table
3-input function

 

3-input AND Gate
C B A Q
0 0 0 0
0 0 1 0
0 1 0 0
0 1 1 0
1 0 0 0
1 0 1 0
1 1 0 0
1 1 1 1
Boolean Expression Q = A.B.C Read as A AND B AND C gives Q

Because the Boolean expression for the AND function is defined as (.), which is a binary operation, AND gates can be cascaded together to form any number of individual inputs. However, commercial available AND gate IC’s are only available in standard 2, 3, or 4-input packages. If additional inputs are required, then standard AND gates will need to be cascaded together to obtain the required input value, for example.

Multi-input AND Gate

6-input AND gate

 

The Boolean Expression for this 6-input AND gate will therefore be:

Q = (A.B).(C.D).(E.F)

In other words:

A AND B AND C AND D AND E AND F gives Q

If the number of inputs required is an odd number of inputs any “unused” inputs can be held HIGH by connecting them directly to the power supply using suitable “Pull-up”